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3 years ago

When paying for a restaurant order, a customer's total for food was $28.50. What is a 16% tip for that total?

Mathematics

1 answer:

vredina [299]3 years ago

6 0

Answer:

33.06

Step-by-step explanation:

you would do 28.5*0.16 and you would get 4.56 ss you would add that to the cost and you would get 33.06

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Find the area of the parallelogram with vertices Ps1, 0, 2d, Qs3, 3, 3d, Rs7, 5, 8d, and Ss5, 2, 7d.

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

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3 years ago

A flagpole is 12.5 m tall. It casts a 17.5 m shadow. How tall is a nearby radio tower that casts a 61.25 m shadow? _____

tresset_1 [31]

Answer:

Step-by-step explanation:

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3 years ago

Kylie is comparing the cost of two housekeeping companies, DoItRight and CleanIt. The table describes the costs for DoItRight.

abruzzese [7]

Answer:

First, find the cost function of DoItRight Housekeeping:

Slope(m) = cost per hour = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{44-26}{3-1.5}=\frac{18}{1.5}=12$

The y-intercept(b), representing the initial cost, can be calculated by substituting in values to the function:

$f(x)=12x+b\\26=12(1.5)+b\\b=26-18=8$

Therefore, the function for two companies are:

The function for DoItRight is $f(x)=12x+8$
The function for CleanIt is $g(x)=10x+16$

When comparing the two functions, it's shown how CleanIt has a greater y-intercept than DoltRight, meaning that CleanIt has a greater initial cost than DotRight. The y-intercept is when the graph intercepts the y-axis, therefore, the coordinates there would be (0, y-value), which, in this case for CleanIt company, will be (0, 16). While CleanIt has a greater y-intercept(initial cost), DoItRight has a greater slope, meaning they cost more per hour.

7 0

3 years ago

What is 60,000+3,000+20+9 in standard form?

kenny6666 [7]

60,000 + 3,000 + 20 + 9

= 63,000 + 29

= 63,029.

Answer: 63,029

Hope this helps have A wonderful Christmas

Step-by-step explanation:

4 0

3 years ago

The shear strength of each of ten test spot welds is determined, yielding the following data (psi). 409 378 358 362 389 404 415

dybincka [34]

Answer:

a. Average shear strength = 385.3 ; standard deviation of shear strength is ±19.25

b. At 95%, X = 1.645σ + μ

c. P(X ≤ 400) = 27.77% = 0.2777

Step-by-step explanation:

Mean = (409 + 378 + 358 + 362 + 389 + 404 + 415 + 375 + 367 + 396)/10

Mean = 3853/10

Mean = 385.3

Therefore, Average shear strength = 385.3

Variance = (409 - 385.3)² + (378 - 385.3)²+ (358 - 385.3)² + (362 - 385.3)²+ (389 - 385.3)²+ (404 - 385.3)²+ (415 - 385.3)²+ (375 - 385.3)²+ (367 - 385.3)²+ (396 - 385.3)²/10

Variance = 3704.1/10 = 370.41

Standard deviation = √370.41 = 19.25

Therefore, standard deviation of shear strength is ±19.25

b. Using normal distribution table at 95%, z = 1.645

z= (X - μ)/σ

Therefore X = 1.645σ + μ

c. X = 400; μ= 385.3 ; σ = 19.25

z= (X - μ)/σ

z= (400 - 385.3)/19.25

z = 0.764

Using the normal distribution table, P = 0.2777

P(X ≤ 400) = 27.77%

8 0

3 years ago