Answer:
![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Step-by-step explanation:
A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".
We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).
If we select a value
we want this:

And we can express this like that:
for each possible i
We assume that the random variable
are independent and
from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

And then cumulative distribution would be expressed like this:



For each value
we can find the dendity function like this:

So then we have the pdf defined, and given by:
and 0 for other case
And now we can find the expected value for the random variable X like this:

![E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}](https://tex.z-dn.net/?f=E%28X%29%3D%20n%20%5Cint_%7B0%7D%5E1%20x%5En%20dx%20%3D%20n%20%5B%5Cfrac%7B1%7D%7Bn%2B1%7D-%20%5Cfrac%7B0%7D%7Bn%2B1%7D%5D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D)
Answer:
x = -1/2 x=-1
Step-by-step explanation:
2x( x+1.5) = -1
Distribute
2x^2 + 3x = -1
Add 1 to each side
2x^2 +3x+1 = 0
Factor
(2x+1) (x+1) =0
Using the zero product property
2x+1 = 0 x+1=0
2x = -1 x=-1
x = -1/2 x=-1
Answer:
37 mph
Step-by-step explanation:
Sum of forces on the car in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces on the car in the x direction:
∑F = ma
-Nμ = ma
-mgμ = ma
-gμ = a
Given μ = 0.75 and g = 32 ft/s²:
a = -(32 ft/s²) (0.75)
a = -24 ft/s²
Use kinematics to find the initial velocity.
v² = v₀² + 2aΔx
(0 ft/s)² = v₀² + 2 (-24 ft/s²) (60 ft)
v₀ ≈ 53.7 ft/s
v₀ ≈ 37 mph
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