Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
You need to give us the equation first, otherwise we can't do it
:|
Answer:
10 1/2
Step-by-step explanation:
We need to convert 1 3/4 to an improper fraction
1 3/4 = (4*1+3)/4 = 7/4
Multiply this by the number of batches
7/4*6 = 42/4 = 21/2
Change this back to a mixed number
2 goes into 21 10 times with 1 left over
10 1/2
Answer:
move the constant to the right hand of the side and change the sign
2x>-0.5-5-5
calculate the difference
2x>-6
divide both sides of the inequality by 2
x>-3
solution X>-3