Answer:
Theorem : Opposite sides of a parallelogram are congruent or equal.
Let us suppose a parallelogram ABCD.
Given:AB\parallel CD and BC\parallel AD (According to the definition of parallelogram)
We have to prove that: AB is congruent to CD and BC is congruent to AD.
Prove: let us take two triangles, \bigtriangleup ACD and\bigtriangleup ABC
In these two triangles, \angle1=\angle2 { By the definition of alternative interior angles}
Similarly, \angle4=\angle3
And, AC=AC (common segment)
By ASA, \bigtriangleup ACD \cong \bigtriangleup ABC
thus By the property of congruent triangle, we can say that corresponding sides of \bigtriangleup ACD and \bigtriangleup ABC are also congruent.
Thus, AB is congruent to CD and BC is congruent to AD.
Answer: 1/4096
Step-by-step explanation:
4^-2 = 1/16
4^-4 = 1/256
multiplying them gives 1/4096
Answer:
the total of straw are going to be 9 and there will be a 1/9 chances of getting the short straw. while each friend picks a straw the probability of getting a short straw is going to be higher because the amount of straws are going to be lessened.
1. x = 15120/12 = 1260 (monthly salary)
2. 1200 x 0.05 = 60 (raise)
Check: 1200+60=1260
HA hypotenuse angle is the correct answer. you can verify the hypotenuse and corresponding angle are equivalent therefore the triangles are equal
