Can sum1 help pls asap

Mathematics

1 answer:

Tems11 [23]3 years ago

5 0

When translated, the x1= (-4,4) y1=(0,6) z1=(2,0)

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In southern California, a growing number of individuals pursuing teaching credentials are choosing paid internships over traditi

Irina18 [472]

Answer:

Candidates are chosen without replacement, thus trials are dependent, meaning that Y has a hypergeometric distribution.

Step-by-step explanation:

Difference between hypergeometric and binomial distributions:

In the hypergeometric distribution, trials are dependent of other trials, while in the binomial distribution, they are independent. This can be examplified that in the hypergeometric distribution, the candidates are chosen from a set without replacement, while in the binomial distribution they are chosen with replacement.

In this question:

Candidates are chosen without replacement, thus trials are dependent, meaning that Y has a hypergeometric distribution.

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3 years ago

Tasia is grocery shoping with her father and wonders how much shopping is left to do we already have 60% of the items on the lis

KatRina [158]

Answer:

Step-by-step explanation:

Percentage of item shopped =60%.

No. of item shopped = 12

Then,

⇒ 60% of total item =12

Total item = 12/60*100 =20.

Therefore, number of item in the list = 20.

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3 years ago

A skier is trying to decide whether or not to buy a season ski pass. a daily pass is $75. A season ski pass is $350. The skier w

pishuonlain [190]

Since the skier has to rent skis for 30 dollars per day with both passes, we can ignore it while solving the question.

A season pass is 350, while a daily pass is 75.

$\frac{350}{75} = \frac{25\times 14}{25\times 3} = \frac{14}{3} = 4 \frac{2}{3}$

So a seasonal pass is equivalent to having 4.6667 daily passes. And you can't buy 0.6667 of a pass.

So, if you went at least 5 days with a seasonal pass, then the seasonal pass would be less expensive than a daily pass.

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3 years ago

Write an equation in point-slope form and in slope-intercept form.

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The point-slope form:

$y-y_1=m(x-x_1)$