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kipiarov [429]
3 years ago
11

Which of the functions below could have created this graph? O A. F(x) = - x ^ 0 + x ^ 3 - x ^ 2 O B. F(x) = - x ^ 2 + 4x ^ 3 - 2

x ^ 2 C. F(x) = x ^ 9 + 12x ^ 8 + x ^ 7 D. F(x) = x ^ 2 + 4x ^ 4 + 20x ^ 2

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

B

Step-by-step explanation:

even roots bounce at (0,0)

negative leading coefficient: initial graph descending to right, curve up

4 local extremes means remaining 5 degree of the function

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A scale model drawing of a backyard is 6 centimeters wide and 8 centimeters long. The scale model uses a scale in which 2 centim
rodikova [14]

Answer:

First you need to divide 1.6 by 2 to get .8 then multiply

.8 x 6 = 4.8

.8 x 8 = 6.4

Then multiply 4.8 by 6.4 and get 30.72

5 0
3 years ago
Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st
SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0
3 years ago
G(a) = 3a + 2<br> f(a)=2a-4<br> Find (g/f)(3)
Basile [38]

Answer:(gf)(3)=g(3)f(3) g(a)=3a+2 or g(3)=3(3)+2=9+2 =11 f(a)=2a−4 f(3)=2(3)−4=6−4=2 g(3)f(3)=112. Answer  

Step-by-step explanation:

7 0
2 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
Guys please help! In triangle CDE, the measure of angle C is 90 degrees, side CD is 15 and DE is 3 more than CE. Find the length
AURORKA [14]
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)

your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°

-> insert those values, with c substituted with b+3 to remove c

c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE

DE=CE+3=36+3=39
4 0
4 years ago
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