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kifflom [539]
3 years ago
8

Help help help please please please

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

Answer:

(-2,2)(5,-6)(5,2)

Step-by-step explanation:

just did this problem

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Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill
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Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}

To find A and k

V(0) = A = 3 million

Hence V = 3e^{kt}

V(6) = 1.5

i.e. 1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552

V(t) = 3e^{-0.11552t}

a) Using the above value of k , we have

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year.

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What is the difference of the two expressions shown below?<br> (3/4x + 2) - (1/4x + 5)
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Answer:

-4. (e) (2-7)(5–3)+32. (-5)(2) +9. -10+9. -8710. 913 - 12 - 13. Ex: Evaluate 4x-7 when x=5. 4(5)-7 ... Ex: In the following exercise we show how two linear expressions are ... equivalency of the two expressions you determined to be equivalent above? ... Ex: Determine an expression that is equivalent to 10x+15? lox+1. 5(2X+3).

Step-by-step explanation:

Here is my notes hope it helped

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2 years ago
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