PLEASE HELP
**ONLY MATH HELPERS**
1 answer:
Perimeter of ABDE = 2+6+2+6 = 16
Perimeter of BCD:
Length BC = sqrt(3^2+4^2)=sqrt(9+16)=sqrt(25) = 5 [using Pythagoras]
Length CD = Length BC = 5
Length BD = 6
Perimeter of BCD = 5+5+6 = 16
=>
ratio of perimeters = 16:16 = 1:1
Area of figure
= area of rectangle + area of triangle
= 2*6 + 6*4/2
= 12+12
=24
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Let number be x and x+13
Then x+x+13=15 (A/q)
2x+13=15
2x=2
X=1
:. X+13= 14
Two numbers are 1 And 14
