<h3>Answer:</h3>
5
<h3>Solution:</h3>
- First, n*7 can be written as 7n.
- Then, 7*5 is equivalent to 35.
- So we have
- 7n=35
- In order to find the value of n, we need to divide both sides by 7:
- n=5
Hope it helps.
Do comment if you have any query.
Answer:
wut????????
Step-by-step explanation:
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Answer:
1st one, x=-1
2nd on, y=2
Step-by-step explanation:
Step-by-step explanation:
![\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\](https://tex.z-dn.net/?f=%5Cfrac%7BsinA%7D%7B1%2BcosA%7D%20%2B%5Cfrac%7B1%2Bcos%7D%7BsinA%7D%20%3D2cosec%5C%5C%5C%5C%5C%5C%5Cfrac%7Bsin%5E%7B2%7DA%2B%281%2Bcos%29%5E%7B2%7D%20%20%7D%7BsinA%281%2BcosA%29%7D%20%5C%5C%5C%5C)
and we have ![sin^{2}+cos^{2} =1](https://tex.z-dn.net/?f=sin%5E%7B2%7D%2Bcos%5E%7B2%7D%20%3D1)
so ![\frac{1+1+2cosA }{sinA(1+cosA)} \\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%2B1%2B2cosA%20%20%7D%7BsinA%281%2BcosA%29%7D%20%5C%5C%5C%5C)
![\frac{2+2cosA }{sinA(1+cosA)} \\\\](https://tex.z-dn.net/?f=%5Cfrac%7B2%2B2cosA%20%20%7D%7BsinA%281%2BcosA%29%7D%20%5C%5C%5C%5C)
we have ![\frac{1}{sin}=cosec\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bsin%7D%3Dcosec%5C%5C)
<em>Finally </em>
<em />
<em>I really hope this helps coz it took much time </em>
Answer:
this isn’t a 100% guaranteed correct answer but maybe the second option saying “PQ and P’G’ are parallel”
(i’m doing the test rn)