The smallest possible product of these four numbers is 59.0625
<h3>How to find the smallest possible product of these four numbers?</h3>
The equation is given as:
a + b + c + d = 12
The numbers are consecutive numbers.
So, we have:
a + a + 1 + a + 2 + a + 3 = 12
Evaluate the like terms
4a = 6
Divide by 4
a = 1.5
The smallest possible product of these four numbers is represented as:
Product = a * (a + 1) * (a + 2) * (a + 3)
This gives
Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)
Evaluate
Product = 59.0625
Hence, the smallest possible product of these four numbers is 59.0625
Read more about consecutive numbers at:
brainly.com/question/10853762
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<4 = <8
3x = x + 402x = 40x = 20
m<4 = 3(20) = (60) o
Answer: y=-3
Step-by-step explanation:
- 3y - 7=5y + 17
-7=8y+17
8y=-24
y=-3
Answer: I think so
Step by step:
Answer:
1.75 hours and 2 Hours
Step-by-step explanation: