Step-by-step explanation:
Subtracting equation (2) from equation (1)
Substituting d = - 3 in equation (1), we find:
Hence, first term is zero.
Answer:
Angle EFG = 104 degrees
Angle GFH = 76 degrees
Step-by-step explanation:
Angle EFG and Angle GFH are a linear pair, which means that they add up to 180 degrees.
Angle EFG = 4n + 20 and Angle GFH = 2n + 34, so 4n + 20 + 2n + 34 = 180.
We can then combine like terms, getting 6n + 54 = 180.
Then, we can subtract both sides by 54, getting 6n = 126.
Lastly, we can divide both sides by 6, getting n = 21.
EDIT - solve for EFG and GFH:
Angle EFG = 4n + 20 = 4(21) + 20 = 104 degrees
Angle GFH = 2n + 34 = 2(21) + 34 = 76 degrees
It would be (2,1)
y=-2*2+5
y=-4+5
y=1
Lets get started :)
f(x) =

- 2
y =

- 2
This is the original equation, and now we have to find the inverse.
When finding the inverse, just flip the variables, x as y and y as x
f ⁻¹(x)
↓
x =

- 2
We have to isolate y as it is our f ⁻¹(x)
Take 2 to the other side { When you see subtraction, you do addition }
x + 2 =

Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y
f ⁻¹ (x) = 9x + 18
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s