1.Simplify.
-2{x}^{2}-4x+13+12{x}^{2}+2x-25−2x2−4x+13+12x2+2x−25
2.Collect like terms.
(-2{x}^{2}+12{x}^{2})+(-4x+2x)+(13-25)(−2x2+12x2)+(−4x+2x)+(13−25)
3.Simplify.
10{x}^{2}-2x-1210x2−2x−12
Step-by-step explanation:
4x² + 11x - 3 = 0
(4x-1)(x+3) = 0
x = 1/4, -3
To solve this we are going to use the half life equation

Where:

is the initial sample

is the time in years

is the half life of the substance

is the remainder quantity after

years
From the problem we know that:



Lets replace those values in our equation to find

:




We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be
91.7 grams.
-3a=-3-2b
a=1+2/3b
Solution
a=1+2/3b

First, solve the parentheses:

Next, the exponential terms

Solve the multiplication:

Add and subtract: