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3 years ago

2 Nal + Pb(NO3)2 2 NaNO3 + Pb12 What are the reactants in this equation?

Chemistry

2 answers:

ivolga24 [154]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf A. \ NaI \ and \ Pb(NO_3)_2}}$

Explanation:

In a chemical reaction, the reactants are the substances that start the reaction and change into other substances. The results at the end of the reaction are products.

Typically, the reactants are to the left of the arrow, while products are to the right.

reactants ⇒ products

We are given this chemical equation:

$2 \ NaI + Pb(NO_3)_2 \rightarrow 2NaNO_3 +PbI_2$

We are asked to find the reactants. Remember, these go into the reaction and are on the left.

$\bold {2 \ NaI + Pb(NO_3)_2 } \rightarrow 2NaNO_3 +PbI_2$

Therefore, the reactants are NaI (sodium iodide) and Pb(NO₃)₂ (lead nitrate). Choice A is correct.

erik [133]3 years ago

3 0

I think it may be A but I’m not to certain

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Ethanol (C2H5OH) melts a - 144 oC and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kj/mol, and its enthalpy of vapo

hammer [34]

Answer:

For a: The total heat required is 36621.5 J

For b: The total heat required is 58944.5 J

Explanation:

For a:

To calculate the heat required at different temperature, we use the equation:

$q=mc\Delta T$ .........(1)

where,

q = heat absorbed

m = mass of substance

$c$ = specific heat capacity of substance

$\Delta T$ = change in temperature

To calculate the amount of heat required at same temperature, we use the equation:

$q=m\times \Delta H$ ........(2)

where,

q = heat absorbed

m = mass of substance

$\Delta H$ = enthalpy of the reaction

The processes involved in the given problem are:

$1.)C_2H_5OH(l)(35^oC)\rightarrow C_2H_5OH(l)(78^oC)\\2.)C_2H_5OH(l)(78^oC)\rightarrow C_2H_5OH(g)(78^oC)$

For process 1:

We are given:

Change in temperature remains the same.

$m=42.0g\\c_l=2.3J/g.K\\T_2=78^oC\\T_1=35^oC\\\Delta T=[T_2-T_1]=[78-35]^oC=43^oC=43K$

Putting values in equation 1, we get:

$q_1=42.0g\times 2.3J/g.K\times 43K\\\\q_1=4153.8J$

For process 2:

We are given:

Conversion factor: 1 kJ = 1000 J

Molar mass of ethanol = 46 g/mol

$m=42.0g\\\Delta H_{vap}=38.56kJ/mol=\frac{35.56kJ}{1mol}\times (\frac{1000J}{1kJ})\times (\frac{1}{46g/mol})=773.04J/g$

Putting values in equation 2, we get:

$q_2=42.0g\times 773.04J/g\\\\q_2=32467.7J$

Total heat required = $[q_1+q_2]$

Total heat required = $[4153.8J+32467.7J]=36621.5J$

Hence, the total heat required is 36621.5 J

For b:

The processes involved in the given problem are:

$1.)C_2H_5OH(s)(-155^oC)\rightarrow C_2H_5OH(s)(-144^oC)\\2.)C_2H_5OH(s)(-144^oC)\rightarrow C_2H_5OH(l)(-144^oC)\\3.)C_2H_5OH(l)(-144^oC)\rightarrow C_2H_5OH(l)(78^oC)\\4.)C_2H_5OH(l)(78^oC)\rightarrow C_2H_5OH(g)(78^oC)$

For process 1:

We are given:

Change in temperature remains the same.

$m=42.0g\\c_s=0.97J/g.K\\T_2=-144^oC\\T_1=-155^oC\\\Delta T=[T_2-T_1]=[-144-(-155)]^oC=11^oC=11K$

Putting values in equation 1, we get:

$q_1=42.0g\times 0.97J/g.K\times 11K\\\\q_1=448.14J$

For process 2:

We are given:

$m=42.0g\\\Delta H_{fusion}=5.02kJ/mol=\frac{5.02kJ}{1mol}\times (\frac{1000J}{1kJ})\times (\frac{1}{46g/mol})=109.13J/g$

Putting values in equation 2, we get:

$q_2=42.0g\times 109.13J/g\\\\q_2=4583.5J$

For process 3:

We are given:

Change in temperature remains the same.

$m=42.0g\\c_l=2.3J/g.K\\T_2=78^oC\\T_1=-144^oC\\\Delta T=[T_2-T_1]=[78-(-144)]^oC=222^oC=222K$

Putting values in equation 1, we get:

$q_3=42.0g\times 2.3J/g.K\times 222K\\\\q_3=21445.2J$

For process 4:

We are given:

$m=42.0g\\\Delta H_{vap}=38.56kJ/mol=\frac{38.56kJ}{1mol}\times (\frac{1000J}{1kJ})\times (\frac{1}{46g/mol})=773.04J/g$

Putting values in equation 2, we get:

$q_4=42.0g\times 773.04J/g\\\\q_4=32467.7J$

Total heat required = $[q_1+q_2+q_3+q_4]$

Total heat required = $[448.14+4583.5+21445.2+32467.7]J=58944.5J$

Hence, the total heat required is 58944.5 J

8 0

3 years ago

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Vera_Pavlovna [14]

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Unbalanced. If the forces on the object is equal and in opposite directions, then the forces are balanced, then there would be no change in motion

what are the three ways to accelerate?
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3 years ago

A plant extract can be obtained with organic solvents such as acetone or ethyl alcohol and is composed of plant pigments such as

iVinArrow [24]

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Which of the following diatomic molecules is joined by a triple covalent bond?

aivan3 [116]

The correct answer is C. In the periodic table nitrogen has 5 valence electrons and needs 3 more electrons to obtain an octet. So it would form three covalent bonds with another nitrogen and that would be a triple bond.

A is incorrect because oxygen is in group 6 and only needs 2 electrons to achieve an octet. So it would form two covalent bonds with the other oxygen to give a double bond.

B is incorrect because Cl is in group 7 and only needs 1 electron to achieve an octet. So it forms a single bond with the other Cl atom.

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3 years ago

3) Explain why elements in the same group similar properties

Alik [6]

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