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EleoNora [17]
3 years ago
9

What happens to a glucose molecule when it loses a hydrogen atom as the result of an oxidation-reduction reaction?

Chemistry
1 answer:
OLEGan [10]3 years ago
7 0

Answer:  oxidized

Explanation:

When a glucose molecule loses a hydrogen atom as the result of an oxidation-reduction reaction, the molecule becomes

oxidized.

Good luck! and sorry if is not the answer ur looking 4!

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Calculate the molality of a solution prepared by dissolving 25.0 g of sodium chloride (NaCl) in 625 g of water
umka2103 [35]

Answer: m= 0.69 m or mol/kg

Explanation: Molality is expressed as moles per unit kilograms of solvent or m= n / kg

First convert 25.0 g NaCl to moles

25.0 g NaCl x 1 mole NaCl / 58 g NaCl

= 0.43 moles NaCl

Next convert 625 g H2O to kilograms

625 g H2O x 1 kg / 1000 g H2O

= 0.625 kg H2O

Substitute the values in the formula

m = n / kg

   = 0.43 mole NaCl / 0.625 kg

   = 0.69 m or mole / kg

6 0
3 years ago
Mg(Oh)2 calculate molar mass
kvv77 [185]

Answer:

From molar mass=total RAM

Mg=24,O=16,H=1

24+(16+1)×2

Therefore Molar mass=58g/mol

4 0
3 years ago
I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
kogti [31]

Answer:

Molecular Mass:

1. 40g per mole

2. 19g per mole

3. 64g per mole

4. 32 g per mole

5. 17g per mole

6. 59.5g per mole

7.58.5 g per mole

8.220g per mole

9. 78g per mole

10. 200g per mole

Explanation:

Molecular Mass = Number of atom x atomic mass of an element

Your Welcome~

8 0
3 years ago
What would happen if you took a normal shaped bottle, sailed it at 1,000 feet, and then carried it up to 14,000 feet
Dovator [93]

it would go 15000 feet

4 0
3 years ago
Read 2 more answers
If a sample of gas has a volume of 100.0ml when the pressure is 50.0kPa, what is volume when the pressure is increased to 400.0k
dalvyx [7]

Answer:

V₂ = 12.5 mL

Explanation:

Given data:

Initial volume = 100.0 mL

Initial pressure = 50.0 KPa

Final volume = ?

Final pressure = 400.0 KPa

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

50.0 KPa × 100.0 mL = 400 KPa × V₂

V₂ = 5000 KPa.mL/ 400 KPa

V₂ = 12.5 mL

6 0
3 years ago
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