Moles of Carbon dioxide : 0.75
<h3>Further explanation</h3>
Given
23 g C₃H₈O₃
Required
Moles of Carbon dioxide
Solution
Reaction
2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O
mol C₃H₈O₃ :
= mass : MW
= 23 g : 92,09382 g/mol
= 0.24975
From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :
= 3/1 x mol C₃H₈O₃
= 3/1 x 0.24975
= 0.74925≈0.750 mol
I believe it is B... because all balance equation are supposed to follow the law of conservation of mass
Answer:
d
Explanation:
a) This is not an equation.
b) This is not an equation.
c) The reactant side has 1 Na and 2 O while the product side has 2 Na and 2 O, therefore it is not balanced
d) The reactant side has 4 H and 4 O and the product side has 4 H and 4 O, therefore it is balanced.
