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vaieri [72.5K]
1 year ago
12

A study of 860 u.s. atms (automated teller machines) found that the average surcharge for withdrawals from a competing bank was

$1.15. (source: public interest research groups) what is known about the atms from a competing bank?
Mathematics
1 answer:
sp2606 [1]1 year ago
7 0

The statement is false as the sample is a few ATMs of the total ATMs in US.

<h3>What do you mean by ATM?</h3>
  • An automated teller machine, or ATM, is a customized computer that makes it simple for bank account holders to manage their money. One can use it to print a statement of account activity or transactions, check account balances, withdraw or deposit money, and even buy stamps.
  • Customers can carry out simple financial transactions using an automated teller machine (ATM), an electronic banking facility, without the assistance of a branch person or teller.
  • With no assistance from the bank, withdraw money whenever you need to. The consumers' privacy is guaranteed. Rupee withdrawals are quicker than bank withdrawals and do not require standing in long lines. Since no bank employees are involved in the transaction, maintenance costs are lower.
  • Two primary types of automated teller machines (ATMs) exist. One is a basic, straightforward device that lets you check your balance, change your PIN, obtain small statements, and get account notifications. The more sophisticated units offer possibilities for a line of credit and bill payment and cash or check deposits.

The sample is only 860 ATMs and not total ATMs in US thus, a sample of 860 ATMs have taken and conducted the survey.

Thus, the statement is false as the sample is a few ATMs of the total ATMs in US.

To learn more about ATMs, refer to:

brainly.com/question/27835947

#SPJ4

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Step-by-step explanation:

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here m = 3, thus

y = 3x + c ← is the partial equation

To find c substitute (9, - 4) into the partial equation

- 4 = 27 + c ⇒ c = - 4 - 27 = - 31

y = 3x - 31 ← equation in slope- intercept form

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Step-by-step explanation:

Answer: B.) 8%

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Step-by-step explanation:

A. part 1: $1.49 for 6 pencils

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2 years ago
Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +
Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

<u>Region inside the quarter disc:</u>

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

<u>Region at the limit of the disc:</u>

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

<u>Analyse in g2:</u>

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

<u>Analyse in g3:</u>

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

<u>Analyse in g1:</u>

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

\lambda_{1}=\sqrt{1/2}*-1 =-0.29

\lambda_{2}=-\sqrt{1/2}*-1 =-1.71

\lambda_{2} give us (x,y) values negatives, outside the region, so we do not take it in account

For \lambda_{1}: S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

<u>Points limits between g1, g2 y g3</u>

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

<u>Conclusion:</u>

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

4 0
3 years ago
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