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2 years ago

Factor the following expression: 15x + 11

Mathematics

2 answers:

Neko [114]2 years ago

8 0

Answer: your answer would be 8x

~I hope that this is correct :-) ~

P.S. I love your pfp I am an army myself lol

Step-by-step explanation:

guajiro [1.7K]2 years ago

7 0

Answer:you cant

Step-by-step explanation:

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Olivia is going to an amusement park. The price of admission into the park is $40, and once she is inside the park, she will hav

svetoff [14.1K]

Answer:

Cost for 13 rides: $92

Cost for r rides: I am guessing it would be 40+4r

Step-by-step explanation:

If you automatically pay 40 dollars to get in, then that is the constant, and paying 4 dollars per ride is a coefficient, so that would be multiplied by how many rides you go on, the variable. Once you plug those into the equation above, you would get 92 dollars for the thirteen rides.

5 0

3 years ago

Read 2 more answers

Find the Inverse of 3x^3-1=y

Anika [276]

$y = 3x^{3} - 1$
$x = 3y^{3} - 1$
$3y^{3} = x + 1$
$y^{3} = \frac{x + 1}{3}$

$y = \sqrt[3]{\frac{x + 1}{3}}$

5 0

3 years ago

Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$