- Cricket = 55%
- Football = 30%
- Other games = Remaining (?)
So, the percent of people who like <u>other games</u> equals:
= 100 – (55 + 30)
= 100 – 85
= 15%
<u>If </u><u>the </u><u>total </u><u>no.</u><u> </u><u>of.</u><u> </u><u>people</u><u> </u><u>is </u><u>6</u><u>0</u><u>,</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u>:
★ Cricket
= 60,00,000 × 55/100
= 33,00,000
★ Football
= 60,00,000 × 30/100
= 18,00,000
★ Other sports
= 60,00,000 × 15/100
= 9,00,000
Sharon would spend $2.50 for the light bulbs she wants.
Sin60 =b/10
<span>√3/2 = b/10
</span>b = <span>√3 / 2 (10)
</span>b = 5<span>√3
</span>
d^2 = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5
sin30 = b/a
1/2 = 5√3 / a
a = 5√3 (2)
a = 10√3
c^2 = (10√3)^2 - (5√3)^2
c^2 = 300 - 75
c^2 = 225
c = 15
so
a =10√3, b = 5√3, c = 15,d = 5
answer is
D. last choice
Answer:
79.17% probability that brandy will roll a strike the first frame of the next game
Step-by-step explanation:
The experimental probability is the probability based on previous outcomes, that is, the number of desired outcomes divided by the number of total outcomes.
While bowling with friends, Brandy rolls a strike in 57 out of 72 frames. What is the experimental probability that brandy will roll a strike the first frame of the next game?
Desired outcomes:
57 strikes
Total outcomes:
72 frames
Probability:
p = 57/72 = 0.7917
79.17% probability that brandy will roll a strike the first frame of the next game
