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padilas [110]
3 years ago
12

Find two numbers, if their sum is 93 and their difference is 9.

Mathematics
2 answers:
kati45 [8]3 years ago
8 0

Answer:

42 and 52

Step-by-step explanation:

ivolga24 [154]3 years ago
4 0

Answer:

51 and 42

Step-by-step explanation:

Use

x + y = 93

x - y = 9

Add those two equations together and you get 2x = 102

*y is not in the equation anymore because y + -y = 0*

Divide both sides by 2

x = 51

plug x into one of the equations; let's use x + y = 93

Then you get, 51 + y = 93

Subtract both sides by 51 and you get y = 42

Plug both in the other equation to make sure the numbers work.

51 + 42 = 93; true

51 - 42 = 9; true

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Question 3 (2 points) Saved Which of the following has the larger area? A rectangle with sides 12 inches and 15 inches. A triang
ZanzabumX [31]

Answer:

rectangle = 180

triangle = 350

the triangle has a much larger area.

350-180=170

the triangle by 17

square inches

5 0
3 years ago
Hi :), im really struggling with this. Just wanted to know if anyone can explain step by step for me please. Id really appreciat
Dvinal [7]

Answer:

314 m²

Step-by-step explanation:

the formula for the surface area of a sphere (As) is

As = 4×pi×r²

the radius r (half of the diameter) is clearly indicated as 5m.

so, As = 4×3.14×5² = 4×3.14×25

I don't even need a calculator for this, as 4×25 = 100

so, As = 100×3.14 = 314

(you know, when multiplying by 10, the decimal point moves right one position. multiply by 100 it moves 2 positions, and so on).

7 0
3 years ago
(a) Find the three-digit number that increases by 30% when each of its
Elden [556K]

Step-by-step explanation:

So a three digit number can be expressed as: 100a + 10b + c where a is the third digit, b is the second digit, and c is the first digit. Or in other words a is the hundreds place, b is the tens place, and c is the ones place. When something "increases" by 30%, it is 130% it's original value, and to calculate how much that is, you simply convert 130% to a decimal by dividing by 100, which gives you 1.30. And since all the digits are increased by 1, you have the equation:

100(a+1) + 10(b+1) + 1(c+1) = 1.30(100a+10b+c)

Distribute the multiplication on the left side:

100a+100+10b+10+c+1=1.30(100a+10b+c)

Distribute the multiplication on the right side:

100a+100+10b+10+c+1=130a+13b+1.3c

Add like terms on the left side:

100a+10b+c+111=130a+13b+1.3c

Subtract 100a, 10b, and c from both sides

111=30a+3b+0.3c

So "technically" you can just plug in any two values, and then solve for the last value, but since you have a 3 digit number, you have the restriction of a < 10, b < 10, and c < 10, and also a, b, and c, should only be integers and all have the same sign or it wouldn't be a 3 digit number.

So let's start with a, since it has the highest coefficient, well you can fit 30 into 111, 3 times without going over so that's the first value

111 = 30(3) + 3b + 0.3c

111 = 90 + 3b + 0.3c

Now subtract the 90 from both sides

21=3b+0.3c

Well 3 can fit into 21, 7 times!

21 = 3(7) + 0.3c

21 = 21 + 0.3c

subtract 21 from both sides

0 = 0.3c

and now obviously c is 0, if you want you can divide both sides by 0.3 but it's a bit redundant

c = 0

This gives you the three values, a=3, b=7, c=0. which is the number 370. Now let's double check. Adding 1 to each digit would give you 481 and 481/370 = 1.3, so it is correct!

part b:

So to prove there is no three digit number, is to realize there is no solution, given the restriction or integers, greater than or equal to 0, and less than 10, and all of them must have the same sign.

So let's start with the same equation except this time instead of 1.3 it's 1.4

100(a+1) + 10(b+1) + 1(c+1) = 1.40(100a+10b+c)

Distribute on the left side;

100a+100+10b+10+c+1=1.40(100a+10b+c)

Distribute on the right side:

100a+100+10b+10+c+1=140a + 14b + 1.4c

Add like terms on left side:

100a + 10b + c + 111 = 140a + 14b + 1.4c

Subtract 100a, 10b, and c from both sides:

111 = 40a + 4b + 0.4c

Now to do the same process, let's start by finding how many times we can fit 40 into 111, and if you're wondering why we start with 40, it's because let's say for example I just say, I can fit another 40 into it, but I decide not to, and let b do that, well even if it's just 40, b will have be at least 10, which does not fit our restrictions, so you have to fit as many 40's into the number first then go the other numbers.

So only 2 40's can fit in 111 without going over the value

111 = 40(2) + 4b + 0.4c

Subtract 80 from both sides

31=4b+0.4c

4 can fit into 31, 7 times

31 = 4(7) + 0.4c

31 = 28 + 0.4c

subtract 28 from both sides

3 = 0.4c

divide both sides by 0.4

7.5 = c.

Since c is not an integer there is no 3 digit number that exists that increases by 40% whenever you increase it by 1.

7 0
2 years ago
HELPPP PLEASE DUE IN 20 minutes
kupik [55]

Answer:

i think its a trick question

Step-by-step explanation:

theres no way theres a righr answer the 20$ on is always ahead

6 0
3 years ago
How do you determine the value of isosceles triangles?
amid [387]

There's really no such thing as the value of a triangle. 

Every triangle has three sides, three angles, a base, a height, and an area,
and there could be problems that ask us to find any one of those. 

Whatever we need to find, the process is always the same: 

-- Take the information that's given.

-- Gather up everything you can remember that talks about a relationship
between what you're given and what you need to find.

-- Use them together to find the missing value.


6 0
3 years ago
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