(-6) + 3 = -3 ;
The negative integer is -6; the positive integer is 3.
We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
Answer:
Step-by-step explanation:
34=-11+7A
We move all terms to the left:
34-(-11+7A)=0
We add all the numbers together, and all the variables
-(7A-11)+34=0
We get rid of parentheses
-7A+11+34=0
We add all the numbers together, and all the variables
-7A+45=0
We move all terms containing A to the left, all other terms to the right
-7A=-45
A=-45/-7
A=6+3/7
Answer:
1
Step-by-step explanation:
Answer: I’m pretty sure the second one (b)
Step-by-step explanation:
