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olasank [31]
3 years ago
9

Which equation describes this relationship?

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0

Answer:

its the first one

Step-by-step explanation:

because you just leave the t alone and bring down the 5 and you get t=5g then since you have to pay 20 your taking away money and using it to pay that bill and therefor it makes it minus and your equation will be t=5g-20 hope this helps :)

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Where did we get one?
77julia77 [94]

Answer:

The -1 came from factoring.

The equation is multiplied by 8 because 8 could be pulled from 16x-8.

16 can be divided by 8 2 times and 8 can only divided by 8 once.

so factoring it makes the equation 8(2x-1)

5 0
3 years ago
A polling company reported that ​% of surveyed adults said that Complete parts​ (a) through​ (d) below.
SOVA2 [1]

Answer:

a) 376.66

b) Option 2: No, the result from part (a) could not be the actual number of adults who said that rising gas prices are "quite annoying" because a count of people must result in a whole.

c) 377

d) 40.77%

Step-by-step explanation:

a) 37% of 1018 is;

37/100 × 1018 = 376.66

b) Thus, the result in a above is not a whole number. Thus;

No, the result from part (a) could not be the actual number of adults who said that rising gas prices are "quite annoying" because a count of people must result in a whole.

c) from a above a, we got a value of 376.66.

Now the actual number would be preferably an integer. Thus, actual number is approximately 377.

d) percentage of respondents said that cellular phones are not at all harmful = 415/1018 × 100% = 40.77%

8 0
3 years ago
Derivative of (a^x/Log a)?​
Zolol [24]
<h2>\large\bold{\underline{\underline{To \: \:  Differentive:-}}}</h2>

\sf{\dfrac{a^x}{log(a)} }

<h3>(OR)</h3>

\sf{\dfrac{a^x}{ln(a)} }

<h2>\large\bold{\underline{\underline{Solution:-}}}</h2>

\sf{Let\ y=\dfrac{a^x}{ln(a)} }

\sf{=\dfrac{d}{dx}\bigg[\dfrac{a^x}{ln(a)}  \bigg] }

<h3>(Linear differentiation)</h3>

\sf{=\dfrac{1}{ln(a)}.\dfrac{d}{dx}(a^x)  }

\sf{=\dfrac{ln(a)a^x}{ln(a)} }

\boxed{\sf{=a^x}}

<h2>\large\bold{\underline{\underline{Applied:-}}}</h2>

<h3>✭ Linear differentiation</h3>

→ \sf{[a.b(x)+c.d(x)]'=a.b'(x)+c.d'(x)}

<h3>✭ Exponential function rule</h3>

→ \sf{(a^x)'=ln(a).a^x}

3 0
3 years ago
Read 2 more answers
Not sure about the rest need help ​
never [62]

I tried to type the answer it said I was wrong
4 0
3 years ago
Which inequality is graphed on the number line shown? A. x &lt; –7 B. x &gt; –7 C. x ≤ –7 D. x ≥ –7
Ad libitum [116K]
We need to see the number line before we can help you.. I'm sorry.
4 0
3 years ago
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