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katen-ka-za [31]
2 years ago
10

You don’t design new software. Instead, you work with software that already exists to be sure that it keeps running smoothly. Wh

ich phase of the software design life cycle are you concerned with?
Group of answer choices
Computers and Technology
2 answers:
Basile [38]2 years ago
8 0

Answer: Maintenance

Explanation: it's maintenance because it's not your software but your making sure it's running smooth so your maintaining the software making sure it's running right so your maintenance maintaining the software

Arada [10]2 years ago
5 0

Answer:

Explanation:

If you are developing software products, run complex projects, you should ... All the same, to make the right choice of an SDLC methodology, you ... Generally, there are stages involved in all the different methodologies. ... You will therefore have to keep both the old and new systems running for some time.

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Assuming each reference costs 1 byte, and each piece of data/info costs 1 byte as well. When will a doubly linked list be more a
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Answer:

The circular individually linked list is more efficient for time sharing process ,when multiple application are running on pc it is responsibility of an output system to put all process on a list and execute them all by giving them piece of time and make them wait when cpu is selected to other process.

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Explanation:

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3 years ago
Consider the following code segment, which is intended to set the Boolean variable inRange to true if the integer value num is g
Natasha_Volkova [10]

Answer:

Option d  num = 50, min = 50, max = 50

Explanation:

Given the code segment:

  1. boolean isBigger;
  2. boolean isSmaller;
  3. boolean inRange;
  4. if (num < max)
  5.        {
  6.            isSmaller = true;
  7.        }
  8.        else {
  9.            isSmaller = false;
  10.        }
  11.        if (num > min)
  12.        {
  13.            isBigger = true;
  14.        }
  15.        else {
  16.            isBigger = false;
  17.        }
  18.        if (isBigger == isSmaller) {
  19.            inRange = true;
  20.        } else {
  21.            inRange = false;
  22.        }

If we have num = 50, min = 50 , max = 50,  the condition num < max will be evaluated to false and therefore isSmaller is set to false.

The condition num > min will be evaluated to false as well and therefore isBigger is set to false.

Since isSmaller and isBigger are both false and therefore isBigger == isSmaller will be evaluated to true and set the inRange = true. This has violated the statement that if the integer value num is greater than min value and less than max value, then only set inRange to true. This is because num = 50 is neither greater than min nor less than max, it is supposedly not in range according to the original intention of the code design.

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