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rewona [7]
3 years ago
14

Larry sent an email to Andy. Andy didn't open Larry's email but still understood what the message was. How did Andy determine th

e message without opening the email?
Computers and Technology
1 answer:
Sladkaya [172]3 years ago
7 0

Andy knew what the message was because of the subject you are required to add in almost all email sights.

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What will be displayed after the following code is executed? def pass_it(x, y): z = x*y result = get_result(z) return(result) de
Rus_ich [418]

Answer:

The output of the following code is "14".  

Explanation:

In the python program firstly we define a function that is  pass_it() function. In this function, we pass the two variable that is x,y. Then we define two variable z and result in the function. The z variable is used to store the multiplication value of the x,y. In the result variable, we use another function that is get_result() function in this function we pass the value of the z variable as a parameter. This function adds a value that is 2 and returns its value. Then we declare a variable that is num1 and num2. In this variable, we assign value that is 3 and 4 and return value of the pass_it() function in the answer variable and print it.  

7 0
3 years ago
Whats an MAR? lolz better not take my points #bonkers
GaryK [48]

Answer:

\huge\mathcal{\fcolorbox{aqua}{azure}{\red{✿ʏᴏᴜʀ- ᴀɴsᴡᴇʀ ♡❖}}}

<em><u>A Medication Administration Record (MAR, or eMAR for electronic versions), commonly referred to as a drug chart, is the report that serves as a legal record of the drugs administered to a patient at a facility by a health care professional. The MAR is a part of a patient's permanent record on their medical chart</u></em>

4 0
2 years ago
Read 2 more answers
Which term collectively describes hard disks, CDs, and flash drives?
N76 [4]
Hard disks, CDs, and flash drives are all storage mediums.
8 0
3 years ago
Read 2 more answers
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
3 years ago
BI systems have eliminated a common organizational problem, which is simultaneously having too much data but somehow not enough.
lyudmila [28]

Answer:

True

Explanation:

Most of the organization suffers from InfoObesity, i.e., too much data without the proper holding structure for this.

Business intelligence abbreviated as BI plays a major role in the determining the planning strategies of an organizations and serves multiple purposes which includes measurement of performance towards business objectives, quantitative analysis, data reporting and sharing, etc.

BI systems helps in eliminating InfoObesity, by manging the data and filtration of the data with proper data structure to serve specific purposes.

8 0
3 years ago
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