Ask question

Ask question

All categories

3 years ago

5

Jayce and Rylee are selling candy bars for a school fund raiser. Rylee sold 84 candy bars and raised $210. If Jayce raised $70 h

ow many candy bars did he sell?

2 answers:

SOVA2 [1]3 years ago

7 0

Jayce sold 28 bc $210/84 bars = $2.50 per bar. $70/2.50 = 28 bars

Dmitriy789 [7]3 years ago

3 0

Answer:28 bars

Step-by-step explanation:

You might be interested in

Prove that: (12^13–12^12+12^11)(11^9–11^8+11^7) is divisible by 3, 7, 19, and 37. The answer should be like: x^b*3*7*19*37. Also

n200080 [17]

Answer:

Step-by-step explanation:

Given (12^13–12^12+12^11)(11^9–11^8+11^7),

(12^13–12^12+12^11)(11^9–11^8+11^7) =

[(12^12)12 – 12^12 + 12^11][(11^8)11 – 11^8 + 11^7)

[(12^12)(12 – 1) + 12^11][(11^8)(11 – 1) + 11^7] =

(12^12(11) + 12^11)(11^8(10) + 11^7) =

(12^11(12x11) + 12^11)(11^7(11x10) + 11^7) =

[(12^11)(12x11 + 1)][(11^7)(11x10 + 1)] =

[(12^11)x(11^7)](12x11 + 1)(11x10 + 1) =

[(12^11)x(11^7)](133 x 111) =

[(12^11)x(11^7)](133 x 111) =

[(12^11)x(11^7)](14763) =

[(12^11)x(11^7)](3x7x19x37)

From here, it is clear that the given number is divisible by 3, 7, 19 and 37.

6 0

3 years ago

How do i solve this ?

Murljashka [212]

You can choose a couple of the x-values and plug each into all of the x's in each equation on the right. Then see which equations give the y-values equal to the y's adjacent to the 3 x-values you used. I chose x=-4 and x=8. Only the 2nd, 3rd, and 5th equations matched with both.

4 0

3 years ago

Alexa has bag of 24 marbles. Ten are red, 8 are blue, and 6 are yellow. What is the probability of choosing two red marbles?

emmainna [20.7K]

Its about a 42 percent chance that both marbles will be red.

6 0

3 years ago

Jalil plays hockey. When Jalil takes a shot on goal, the probability that he scores is . If Jalil takes 80 shots on goal in a se

lions [1.4K]

Answer:

its 60

Step-by-step explanation:

7 0

3 years ago

Elena is buying cups and plates for her party. Cups are sold in packs of 8 and plates are sold in packs of 6. She wants to have

Svet_ta [14]

Answer:

For 80 people, Elena would need

14 packs of plates and 10 packs of cups

She would have at least 80 of each.

I am not completely sure of this, sorry if wrong.

Step-by-step explanation:

80 people

8 cups per pack

6 plates per pack

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84

LCM (least common multiple) = 24

8 0

3 years ago

Read 2 more answers