Answer:
Neither
Explanation:
Even though the average between the 4 measurements is 7.45, the measurements are not accurate. This is probably due to the pH meter being out of calibration or because there is some contamination in the buffer solution
N₂H₄ + 2H₂O₂ → N₂ + 4H₂O
mol = mass ÷ molar mass
If mass of hydrazine (N₂H₄) = 5.29 g
then mol of hydrazine = 5.29 g ÷ ((14 ×2) + (1 × 4))
= 0.165 mol
mole ratio of hydrazine to Nitogen is 1 : 1
∴ if moles of hydrazine = 0.165 mol
then moles of nitrogen = 0.165 mol
Mass = mol × molar mass
Since mol of nitrogen (N₂) = 0.165
then mass of hydrazine = 0.165 × (14 × 2)
= 4.62 g
53.491 g/mol
Hope it helps. :)
True. A mole of anything has the same amount of molecules. 1 mole = 6.022 x 1023 molecules
Answer: 7.8 moles of NaCl result from the complete reaction of 3.9 mol of 
Explanation:
To calculate the moles :
As 
is the excess reagent, is the limiting reagent as it limits the formation of product.
According to stoichiometry :
1 mole of gives = 2 moles of 
Thus 3.9 moles of will give=
of
7.8 moles of NaCl result from the complete reaction of 3.9 mol of
