Answer:
a. 2.748
b. 68.91
c. 1.45%
d. 37.84%
Explanation:
To determine the:
a. The aggregate's bulk Saturated Surface Dry specific gravity
Given:
The mass of the moist aggregate sample is 5,229 g.
The mass of the oven-dried aggregate is 5,306 g.
The mass of the aggregate submerged in water is 5,229 g.
The mass of the Saturated Surface Dry aggregate is 3,298 g.
The aggregate's bulk SSD specific gravity =the dry weight ÷ ( the SSD weight - the submerged weight)
Given:
The mass of the oven-dried aggregate is 5,306 g.
The mass of the Saturated Surface Dry aggregate is 3,298 g.
The mass of the aggregate submerged in water is 5,229 g.
= 5,306 ÷ ( 3,298 - 5,229)
= 5,306 ÷ 1,931 = 2.748
b. The aggregate appearance specific gravity
the aggregate apparent specific gravity = the dry weight ÷ (the dry weight - the submerged weight)
Given:
The mass of the oven-dried aggregate is 5,306 g.
The mass of the aggregate submerged in water is 5,229 g
The aggregate apparent specific gravity = 5,306 ÷ (5,306 - 5,229)
The aggregate apparent specific gravity = 68.91
c. The moist content of stockpile aggregate
The moisture content of stockpile aggregate = ( the moist aggregate weight - the dry weight) ÷ the dry weight
Given:
The mass of the moist aggregate sample is 5,229 g.
The mass of the oven-dried aggregate is 5,306 g
The moisture content of stockpile aggregate = (5,229 - 5,306) ÷ 5,306
The moisture content of stockpile aggregate = 0.0147 x 100% (when expressed in percentage) = 1.45%
d. Absorption
Absorption = (mass of the Saturated Surface Dry aggregate - mass of the oven-dried aggregate) ÷ mass of the oven-dried aggregate x 100%
Given:
The mass of the Saturated Surface Dry aggregate is 3,298 g
The mass of the oven-dried aggregate is 5,306 g.
Absorption = (3,298 - 5,306) ÷ 5,306 x 100% = 37.84%
