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Julli [10]
3 years ago
9

Moving truck makes the displacement of (180m) toward east in period of(9.0s). What is the average velocity of the truck?someone

please help!!
Business
2 answers:
makvit [3.9K]3 years ago
6 0

Answer:

20m/s due east

Explanation:

Given parameters:

Displacement  = 180m due east

Time taken = 9s

Unknown:

Average velocity of the truck  = ?

Solution:

The average velocity is the displacement divided by the time taken;

   Average velocity  = \frac{displacement}{time}  

Insert the parameters and solve;

 Average velocity = \frac{180}{9}   = 20m/s due east

Lerok [7]3 years ago
5 0

\mathrm {Hey, there!}

Let's solve your problem:

20 m/s due east is your answer.

For this question, we will use the displacement method.

The displacement method states:

You divide the larger number by the smaller number.

--- \mathrm {Equation} - \mathrm {180m / 9.0 = 20.0}

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