The theoretical yield of 18 gram of
is 162 gram of
.
The amount of a product produced by a reaction is generally expressed as a percentage of the reaction's yield. The amount of product that stoichiometry predicts is known as the theoretical yield, but the amount that would be actually achieved is known as the actual yield.
The balanced chemical equation is :
→ ![2H_{2} O](https://tex.z-dn.net/?f=2H_%7B2%7D%20O)
It is known that the molar mass of water is 18 gram /mol and 2 gram per mole of
.
18g
(1 mol
(/2 g
()(2 mol
/ 2 mol
()(18 g
/1 mol
) = 162 g
.
Theoretical yield will be 162 gram.
So, the theoretical yield of 18 gram of
is 162 gram of
.
To know more about the theoretical yield
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Answer:
low boiling points and melting points
various colors
poor conductors of heat and electricity
brittle solids
<u>Answer:</u> The heat of formation of oleic acid is -94.12 kJ/mol
<u>Explanation:</u>
We are given:
Heat of combustion of oleic acid = ![-1.11\times 10^4kJ/mol](https://tex.z-dn.net/?f=-1.11%5Ctimes%2010%5E4kJ%2Fmol)
The chemical equation for the combustion of oleic acid follows:
![C_{18}H_{34}O_2(l)+\frac{51}{2}O_2(g)\rightarrow 18CO_2(g)+17H_2O(g);\Delta H^o=-1.11\times 10^4kJ](https://tex.z-dn.net/?f=C_%7B18%7DH_%7B34%7DO_2%28l%29%2B%5Cfrac%7B51%7D%7B2%7DO_2%28g%29%5Crightarrow%2018CO_2%28g%29%2B17H_2O%28g%29%3B%5CDelta%20H%5Eo%3D-1.11%5Ctimes%2010%5E4kJ)
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as ![\Delta H^o](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo)
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(18\times \Delta H^o_f_{(CO_2(g))})+(17\times \Delta H^o_f_{(H_2O)})]-[(1\times \Delta H^o_f_{(C_{18}H_{34}O_2(l))})+(\frac{51}{2}\times \Delta H^o_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%2818%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%29%2B%2817%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2O%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%29%2B%28%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:
![\Delta H^o_f_{(CO_2(g))}=-393.51kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2)}=0kJ/mol\\\Delta H^o_{rxn}=-1.11\times 10^4kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%3D-393.51kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28H_2O%28g%29%29%7D%3D-241.82kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28O_2%29%7D%3D0kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D-1.11%5Ctimes%2010%5E4kJ)
Putting values in above equation, we get:
![-1.11\times 10^4=[(18\times (-393.51))+(17\times (-241.82))]-[(1\times \Delta H^o_f_{(C_{18}H_{34}O_2(l))})+(\frac{51}{2}\times 0)]\\\\\Delta H^o_f_{(C_{18}H_{34}O_2(l))}=-94.12kJ/mol](https://tex.z-dn.net/?f=-1.11%5Ctimes%2010%5E4%3D%5B%2818%5Ctimes%20%28-393.51%29%29%2B%2817%5Ctimes%20%28-241.82%29%29%5D-%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%29%2B%28%5Cfrac%7B51%7D%7B2%7D%5Ctimes%200%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_f_%7B%28C_%7B18%7DH_%7B34%7DO_2%28l%29%29%7D%3D-94.12kJ%2Fmol)
Hence, the heat of formation of oleic acid is -94.12 kJ/mol
Answer:
In physics, a fluid is a liquid, gas, or other material that continuously deforms (flows) under an applied shear stress, or external force.
Explanation:
They have zero shear modulus, or, in simpler terms, are substances which cannot resist any shear force applied to them.
It is effected by diffusion (the power of smell and wind spread) but a solid is not.