No, Silver will not react with dilute sulfuric acid.
<u>Explanation:</u>
As Silver has the least reactivity, it is not capable to reduce hydrogen ion from sulfuric acid, even when the acid is in concentrated state. But if the concentrated acids are heated then the Silver may form Ag+ ions.
But silver (Ag) can react with the hot concentrated sulfuric acids (
). As mentioned in below to equation.
So if dilute sulfuric acid is used then there will not be any kind of reaction with silver ions.
Answer:In general, yes. Usually, you talk about the reflectivity/emissivity of a surface rather than an object. Typically, you’d find a coefficient of emissivity (since emission and absorption are normally equivalent processes in reverse) for the surface, ideally as a function of wavelength and incident angle. Then you apply that coefficient to all light striking the object.
Assuming an opaque object, reflectivity (call it R) has a simple relationship to emissivity (call it E): R=1-E. You can measure reflectivity with a calibrated light source and light sensor, for example. It’s a little trickier, but you can also measure emissivity through techniques like calorimetry, where you measure how much something heats up to figure out how much energy was deposited; again, a calibrated light source can be used to direct a certain amount of power onto a test object, and the heating tells you how much power is retained. You can also get emissivity by heating an object and observing how much power it emits by blackbody radiation.
To be really thorough, you might also want to measure transmissivity, in case the object isn’t opaque. If we call transmissivity “T,” we really have to write R+E+T=1 (which just says that all the incident light has to either reflect, absorb, or pass through).
If the object is something celestial, of course, it’s harder to use these methods, but not impossible. For example, we can measure how much light the full moon reflects, and knowing how much light hits it from the sun, we can find the reflectivity; in principle, we could use our knowledge of how much the surface of the moon is heated by the sun to find the emissivity, as well. For that kind of calculation, it’s important to know how large and how distant an object is, to figure out how much of its reflected light makes it back to you.
Explanation:
Part I4Fe + 3O2 -> 2Fe2O3. This is redox reaction and the reaction is also called rusting. The reaction can be classified as a combination reaction.
Part II2H2O2 -> 2H2O + O2. The evolution of bubbles was the indication that a chemical reaction was taking place.
Part III.2Zn + 2HCl -> H2 + ZnCl2. A displacement reaction occurs in the reaction. A metal and a acid are common reactants in this reaction.
Part IV.NaHCO3 + CH3COOH -> CH3COONa + H2CO3
The second reaction isH2CO3 -> CO2 + H2O
which is decomposition reaction.
Answer:
The concentrations of A, B, and C at equilibrium:
[A] = 0.0 M
[B] = 2.7 M
[C] = 2.4 M
Explanation:
Concentration of 1.80 mol of A in 1.00 L container :
![[A]=\frac{1.80 mol}{1.00 L}=1.80 M](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B1.80%20mol%7D%7B1.00%20L%7D%3D1.80%20M)
Concentration of 3.90 mol of B in 1.00 L container :
![[B]=\frac{3.90 mol}{1.00 L}=3.90 M](https://tex.z-dn.net/?f=%5BB%5D%3D%5Cfrac%7B3.90%20mol%7D%7B1.00%20L%7D%3D3.90%20M)
Initially
1.80 M 3.90 M 0
At equilibrium
(1.80-3x)M (3.90-2x) 4x
The expression of an equilibrium constant is given by :
![K_c=\frac{[C]^4}{[A]^3[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E4%7D%7B%5BA%5D%5E3%5BB%5D%5E2%7D)
Solving for x:
x = 0.600
The concentrations of A, B, and C at equilibrium:
[A] = [1.80-3x]=[1.80-3 × 0.600]= 0 M
[B] = [3.90-2x] = [3.90-2 × 0.600] = 2.7 M
[C] = [4x] =[4 × 0.600 M] = 2.4 M
Answer: a) 
b) 
c) 
d) 
e) 
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
he salts which are soluble in water are designated by symbol (aq), those in solid form are represented by (s), those in liquid form are represented by (l) and those in gaseous form are represented by (g) after their chemical formulas.
a) decomposition of solid calcium carbonate from seashells to form solid calcium oxide and gaseous carbon dioxide:
b) formation of solid calcium hydroxide as the only product from the reaction of the solid calcium oxide with liquid water
c) calcium hydroxide is then added to the seawater, reacting with dissolved magnesium chloride to yield solid magnesium hydroxide and aqueous calcium chloride
d) solid hydroxide is added to a hydrochloric acid solution producing dissolved magnesium chloride and liquid water
e) magnesium chloride is melted and electrolyzed metal and diatomic chlorine gas.
