If I'm understanding the question right:
12) 24 x 10^4
13) 93,000,000
Answer:

Step-by-step explanation:
The parent function denotes the simplest function (free from any horizontal/vertical stretch/compression) that represents a family of functions. In this case the term 1/4 indicates a horizontal stretch and should be removed to find the parent function of
. From here we're in simplest form, since
or others represent a completely different family of functions and cannot be obtained from horizontal/vertical stretches/compressions.
(5,3) is the answer for the current question
Answer:
Step-by-step explanation:
<h3>Given GP</h3>
<h3>To find</h3>
<h3>Solution</h3>
<u>Substitute ar in the second equation</u>
- ar⁵= 16
- 4r⁴ = 16
- r⁴ = 4
- r = √2
<u>Then finding a₄</u>
- a₄ = a₂*r² = 4*(√2)² = 4*2= 8
<u>Annotation</u>General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.
One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)
The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)
Plug the d-v-t relationship to the second equationd₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262
Plug the v₁ as (v₂+5) from the first equation2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.Find the velocity of the first car, use the first equationv₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.
Answer

