The solution of this equation is 16/15
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
<span>6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player. </span>
<span>So the bleachers are 9/2 x 6 ft = 27 ft. </span>
<span>For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216. </span>
<span>So the stage will have dimensions 216 times larger than 1.75" by 3". </span>
<span>That would be 31ft 6ins x 54ft. </span>
<span>(x - h)² + (y - k)² = r²
is the equation of the circle with center (h, k) and radius r units.
Thus (x + 2)² + y² = 10 is the equation of a circle whose center is at the point (-2, 0) and having a radius of √10 units<u>
</u></span>
Answer:
x^5/6+2x^7/3
Step-by-step explanation:
hoped this was helpful! c:
Answer:
24 square cm
Step-by-step explanation:
