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Ede4ka [16]
3 years ago
7

Solve for x in the equation 3x + 8 = x - 12.​

Mathematics
2 answers:
Yuliya22 [10]3 years ago
5 0

Answer:

x = -10

Step-by-step explanation:

Combine like terms and solve for x

3x + 8 = x - 12

3x= x - 20

2x = -20

x = -10

Drupady [299]3 years ago
3 0

Answer:

The answer is x = -10

Step-by-step explanation:

3 x -10 + 8= -22

-10 - 12 = -22

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Can someone help me. <br><br><br> Which equation represents the data in the table?
nydimaria [60]

Answer:

D) t=4d+5

Step-by-step explanation:

If d=1,

t=4\times 1+5\\t=9

If d=2,

t=4\times2+5\\=8+5\\=13

If d=4,

t=4\times4+5\\=16+5\\=21

Therefore,

t=4d+5

8 0
2 years ago
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89 x , 16x , -30x please show your work .
natima [27]

Answer:

Step-by-step explanation:

89x = 89 * x

16x = 2 * 2 * 2 * 2 * x

-30x = -1 * 2 * 5 * 3 * x

x is the only factor that is common in all three.

GCF = x

5 0
3 years ago
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Plz help me!!! it is due tomorrow!!!!
AlekseyPX
X is less then or equal to 8
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7 0
4 years ago
1.) What is the value of cosθ given that (−5, −4) is a point on the terminal side of θ?
jeka57 [31]

Answer:

1) C

2) D

Step-by-step explanation:

1)

We want to find the value of cos(θ) given that (-5, -4) is a point on the terminal side of θ.

This is represented by the diagram below.

Recall that cosine is the ratio of the adjacent side to the hypotenuse.

Find the hypotenuse:

\displaystlye \begin{aligned} a^2 + b^2 &= c^2 \\ c &= \sqrt{a^2 + b^2} \\ &= \sqrt{(4)^2 + (5)^2} \\ &= \sqrt{41}\end{aligned}

The adjacent side with respect to θ is -5 and the hypotenuse is √41. Hence:

\displaystyle \begin{aligned}\cos \theta &= \frac{(-5)}{(\sqrt{41})} \\ \\ &= - \frac{5\sqrt{41}}{41}  \end{aligned}

Our answer is C.

2)

We want to find the value of sin(θ) given that (-6, -8) is a point on the terminal side of θ.

This is represented in the diagram below.

Likewise, find the hypotenuse:

\displaystyle c = \sqrt{(-6)^2 + (-8)^2} = 10

Sine is given by the ratio of the opposite side to the hypotenuse.

The opposite side with respect to θ is -8 and the hypotenuse is 10. Hence:

\displaystyle \begin{aligned}\sin \theta &= \frac{(-8)}{(10)} \\ \\ &= -\frac{4}{5} \end{aligned}

Our answer is D.

8 0
3 years ago
What are the solutions to the quadratic equation x2 – 16 = 0?
exis [7]

Answer:

2nd choice: x=4 and x=-4

Step-by-step explanation:

x^2 - 16 = 0 can be simplified to (x-4)(x+4)=0

x-4 = 0 so x = 4

and x + 4 = 0 so x = -4

4 0
3 years ago
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