Y = 2^x and y = log₂x
Exponents and logs (to the same base = 2) are inverses of each other.
All inverse functions are symmetric about line y = x
y = log₂x is NOT the logarithmic form of y = 2^x
The logarithmic form of y = 2^x is x = log₂y (NOT y = log₂x)
Answer: A, C
Answer:
3. BDE is congruent to BAC; corresponding angles postulate
4. B is congruent to B; reflexive property of equality
Step-by-step explanation:
I took the test.
Answer:
X = 119, Y = 61, Z = 119
Step-by-step explanation:
These are supplementary angles and equal 180.
180 - 61 = 119
Opposite angles are congruent
Answer: 7
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. You know that a multiplication has the following form:
a*b=c
Where a and b are the factors and c is the product.
2. You know one of the factor, then you can find the second one as following:
12*b=84
b=84/12
b=7
Therefore the answer is 7.
2)
P(4,-4) -->(-4, 7)
4 - 8 = -4 -------->left 8
-4 + 11 = 7 -------->up 11
Answer: left 8; up 11
3)
C(3,-1) , left 4 up 1
3 - 4 = -1 -------->left 4
-1 + 1 = 0 -------->up 1
a)
(x , y) -->(x - 4 , y +1)
C(3, -1) -->C'(-1 , 0)
b)
(x , y) --> (x - 4, y + 1); (-1 , 0)