The discontinuity occurs at x = 0, since that is the only "problem" place in the graph that makes the function undefined. A vertical asymptote exists there. It is nonremoveable.
Point slope form is y-(-4) = 1/2(x-(-2)
y+4 =1/2 (x+2)
now the standard form 2y+8=x+2
so -x+2y=-6 is the equation for line p in standard form
Answer:
<em>No </em><em>9</em><em>7</em><em> </em><em>is </em><em>not </em><em>an </em><em>irrational </em><em>number </em>
Step-by-step explanation:
Be happy
Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8
Hope this will help you!
-8
f(x) is y, in which x is the independent variable
when x = 5, y = -8
