It's easy to show that
is strictly increasing on
. This means

and

Then the integral is bounded by


Consider right triangles BTZ and BUZ.
ZB = ZB (Common)
ZT = ZU (Given)
Therefore, ΔBTZ ≅ ΔBUZ (By RHS theorem)
Hence, by CPCTC,
∠BTZ = ∠BUZ
Yes.
3y=2x +1
3 (1) = 2 (1) +1
(3,3)
(1,1) is a solution
Answer:
(x) = 
Step-by-step explanation:
Let y = f(x) and rearrange making x the subject
y = 5 - 2x ( add 2x to both sides )
2x + y = 5 ( subtract y from both sides )
2x = 5 - y ( divide both sides by 2 )
x = 
Change y back into terms of x
(x) = 
Answer:
504
Step-by-step explanation:
7*8*9=504