1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
3 years ago
11

John began his job making $125 the first week. After that he ws paid $6.25 per hour. Write the equation in slope intercept form

to represent the situation.
Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0

a)  y= 0.05x + 16

b)  y= 6.25x + 125

c)  y= 2x + 10

d)  y= 3x + 5

Answer: B) y = 6.25x + 125

dlinn [17]3 years ago
5 0

Answer:

y=6.25x+125

Step-by-step explanation:

Given that,

John began his job making $125 the first week. After that he was paid $6.25 per hour.

Here $125 is fixed and $6.25 increase per hour. It means we can write the equation as follows :

y = 125 + 6.25 x

The general equation for the slope-intercept form is given by :

y = mx+x

m is slope

So, the equation in slope intercept form is given by :

y=6.25x+125

Hence, this is the required solution.

You might be interested in
So the equation 12 y equals 132 the equation 12 y equals 132
OlgaM077 [116]
12y = 132

Now, solve for y.

Do the inverse operation.

12y = 132
12y/12 = 132/12
y= 132/12
y= 11

Equation: 12y = 132
Y equals: 11
4 0
3 years ago
(-2.4) - 0.8 times -4.3
ICE Princess25 [194]

Answer is this:

1.04                      

7 0
3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
Robin is filling her salt shaker from a cylindrical container that is full of salt. Her salt shaker in the shape of a cone has a
Anettt [7]

Answer:

3 times

Step-by-step explanation:

It's three since when you count the area's are the 3 times different which means the answer is 3

7 0
3 years ago
John took a quiz and got 42 out of 50. What is amount in decimals and percentages
Norma-Jean [14]

Answer:

0.84, 84%

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • Plz help me with this math problem
    10·1 answer
  • Tina sells homemade crafts online. Her online
    6·2 answers
  • Of the children at Molly's daycare, 1/8 are boys and 2/5 of the boys are under 1 year old. How many boys at the daycare are unde
    11·1 answer
  • X+ 4x + 6x what is the answer in struggling really bad#
    9·2 answers
  • Which statement is true about the potential
    14·2 answers
  • A carpenter is creating a circular wooden table with a radius of 4 feet and needs to know the area of the table to purchase the
    12·2 answers
  • When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
    14·1 answer
  • !HELP!
    15·2 answers
  • Abigail has $356 in her bank account. She earns simple interest on her money at a rate of 3% per year for a total of five years.
    7·1 answer
  • Which of the following functions is graphed below
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!