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Daniel [21]
3 years ago
7

Students in 7th grade took a standardized math test that they also had taken in 5th grade. The collected data showed that in two

years the median increased by three points, and the mean increased by around two and a half points. In terms of the context, what can you infer?
Mathematics
2 answers:
Arada [10]3 years ago
6 0
<span>In general, the students increased their standardized math scores from 5th grade to 7th grade. The students might be more familiar with the exam and they have learned more in their math classes.</span>
Svetllana [295]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that

Students in 7th grade took a standardized math test that they also had taken in 5th grade. The collected data showed that in two years the median increased by three points, and the mean increased by around two and a half points. In terms of the context,

This proves that there is overall improvement in the grades of students.

But there is a small difference between mean increase and median increase.

While median increased 3 points, mean increased only by 2.5 points.  This implies there exists unusually low level iq students who had unusually low score thus affecting mean to be low.

Special training should be given to those students.

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Alex and Peter win some money and share it in the ratio 6:1. Alex gets £50 more than Peter. How much did they get altogether?
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Alex = 6x
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There is a 30 percent chance that A can fix her busted computer. If A cannot, then there is a 40 percent chance that her friend
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Answer:

(a) 0.70

(b) 0.40

Step-by-step explanation:

Mutually-exclusive events are those events which cannot occur together.

Consider that events X and Y are mutually exclusive.

P (X and Y) = 0

Here the two events can be defined as follows:

A = A can fix the busted computer

B = B can fix the busted computer

The information provided are as follows:

P (A) = 0.30

P (B) = 0.40

If A cannot, then there is a chance that her friend B can fix it.

The above statement suggest that the events A and B are mutually exclusive, i.e. if A can fix the computer then B does not have to and if cannot then only B will fix it.

That is, P (A and B) = 0.

(a)

Compute the probability it will be fixed by either A or B as follows:

P (A or B) = P (A) + P (B) - P (A and B)

                = 0.30 + 0.40 - 0

                = 0.70

Thus, the probability it will be fixed by either A or B is 0.70.

(b)

Compute the probability that if it is fixed it will be fixed by B as follows:

P (not A and B) = P (B) - P (A and B)

                         = 0.40 - 0

                         = 0.40

Thus, the probability that if it is fixed it will be fixed by B is 0.40.

8 0
3 years ago
A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 9% vinegar, and the second brand co
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Let the amount of the first brand be x, and let the amount of the second brand be y.
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x + y = 240 ..............(2)
y = 240 - x .......................(3)
Plugging the value for y from equation (3) into equation (1), we get:
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3 years ago
Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The goal is to sh
natulia [17]

Complete Question

Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.

Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.

Answer:

P(18) is true

P(19) is true

P(20) is true

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Step-by-step explanation:

a. When n = 18

18 cents can be formed using two 7cents and one 4cents

i.e. 2 * 7 + 4 = 18

So, P(18) is true

b. When n = 19

19 cents can be formed using one 7cents and three 4cents

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So, P(19) is true

c. When n = 20

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So, P(20) is true

d. When n = 21

18 cents can be formed using three 7cents

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So, P(21) is true

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