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2 years ago

I need help.... (or just the answer)

Mathematics

1 answer:

Serjik [45]2 years ago

7 0

Answer:

Answers on the image attached drawn.

Step-by-step explanation:

Hello there, it seems a little dark in the room. You might want to try turning on the light. I added the image attached to this to solve your questions. Hope this helps.

For 1.) , the linear system is only one solution.

On 2.) , they overlap, therefore, it has infinite solutions.

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What is z? 5z+8=4z+20 Once again im struggling and need help fast..=)

mixas84 [53]

Z= 12 hope this helps

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3 years ago

Read 2 more answers

A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d

Alenkasestr [34]

Answer:

μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

Distance 1:

- Ff*d₁ = Ef - Ei

⇒ - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ

⇒ - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ (I)

Distance 2:

- Ff*d₂ = Ef - Ei

⇒ - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒ μ*g*d₂ = 0.5*v² (II)

If we apply (I) + (II)

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ (III)

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁ ⇒ vf² = 2*g*Sin θ*d₁ = v²

then (from the equation III) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒ μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒ μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK ⇒ - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁ ⇒ d₂ = Sin θ*d₁ / μ

3 0

3 years ago

Find the sum of the first 6 terms in the sequence -5 -25 -125 -625

sashaice [31]

This is a geometric sequence, so use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -5
r is the common ratio, 5
and n is the number of terms

Thus,
Sum = ((-5)(5^6 - 1))/(5-1) = -19530

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3 years ago

Find the solutions of the quadratic equation <img src="https://tex.z-dn.net/?f=-x%5E2%2B7x-14%3D0" id="TexFormula1" title="-x^2+

Vinvika [58]

Answer:

Step-by-step explanation:

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2 years ago

Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time. The bank ha

love history [14]

Answer:

To be able to approximate the sampling distribution with a normal model, it is needed that $np \geq 10$ and $n(1-p) \geq 10$ , and both conditions are satisfied in this problem.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will make payments on time, or they won't. The probability of a person making the payment on time is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The sampling distribution can be approximated to a normal model if:

$np \geq 10$ and $n(1-p) \geq 10$

Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time.

This means that $p = 0.089$

The bank has recently approved 220 loans.

This means that $n = 220$

What must be true to be able to approximate the sampling distribution with a normal model?

$np = 220*0.089 = 19.58 \geq 10$

$n(1-p) = 220*0.911 = 200.42 \geq 10$

To be able to approximate the sampling distribution with a normal model, it is needed that $np \geq 10$ and $n(1-p) \geq 10$ , and both conditions are satisfied in this problem.

3 0

2 years ago

I need help.... (or just the answer) ​

I need help.... (or just the answer)