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Ivenika [448]
3 years ago
15

Solve for x 4^x/9^x=½​

Mathematics
1 answer:
kirill115 [55]3 years ago
3 0

Answer:

x = 0.85476

Step-by-step explanation:

4ˣ/9ˣ=½

9ˣ / 4ˣ = 2

(9/4)ˣ = 2

2.25ˣ = 2 .... aⁿ = x     logₐx = n

log₂.₂₅2 = x

x = 0.85476

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In the coordinate plane, what is the length of the line segment that connects points at (5, 4) and (−3, −1) ? Enter your answer
stiks02 [169]
The distance between two points knowing theirs coordinates:

AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(5,-4) & B(-3,-1) Given
                                                A(x₁,y₁) & B(x₂,y₂)

AB =√[(-3-5))²+(-1-(-4)²] =√(73) = 8.381 ≈ 5.44 units
3 0
3 years ago
(2x³)⁴= ? What is the right answer, with full explanation please:
netineya [11]
So you multiply the 4th power

2 times 4 is 8
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7 0
3 years ago
Read 2 more answers
Use the divergence theorem to find the outward flux of the vector field F(x,y,z)=2x2i+5y2j+3z2k across the boundary of the recta
aksik [14]

Answer:

The answer is "120".

Step-by-step explanation:

Given values:

F(x,y,z)=2x^2i+5y^2j+3z^2k \\

differentiate the above value:

div F =2 \frac{x^2i}{\partial x}+5 \frac{y^2j}{\partial y}+3 \frac{z^2k }{\partial z}  \\

        = 4x+10y+6z

\ flu \ of \ x = \int  \int div F dx

              = \int\limits^1_0 \int\limits^3_0 \int\limits^1_0 {(4x+10y+6z)} \, dx \, dy \, dz \\\\ = \int\limits^1_0 \int\limits^3_0 {(4xz+10yz+6z^2)}^{1}_{0} \, dx \, dy  \\\\ = \int\limits^1_0 \int\limits^3_0 {(4x+10y+6)} \, dx \, dy  \\\\ = \int\limits^1_0  {(4xy+10y^2+6y)}^3_{0} \, dx   \\\\ = \int\limits^1_0  {(12x+90+18)}\, dx   \\\\= {(12x^2+90x+18x)}^{1}_{0}   \\\\= {(12+90+18)}   \\\\=30+90\\\\= 120

6 0
3 years ago
What is the highest mulitipul of 2&3
yKpoI14uk [10]
Hope it's 30. .....................
5 0
3 years ago
X + 4 is prime x2 – 9 can be factored using the formula.
Anna71 [15]

We are given two binomials: x+4 , x^2-9.

x+4 can't be factored. Therefore,  it is a prime.

Let us work on x^2-9.

9 could be written as 3^2.

Therefore, x^2-9 = x^2 - 3^2.

Now, we can apply difference of the squares formula to factor it.

We know a^2 -b^2 = (a-b) (a+b).

Therefore,  x^2 - 3^2 can be factored as (x-3) (x+3).

So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).

3 0
3 years ago
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