H (x) =4x-2 complete the function table
1 answer:
<em>Note: </em>
<em>You did not mention the table of the points. But, I would try to clear your concept by taking 6 sample points.</em>
Answer:
The table and the graph of the function h(x) = 4x-2 is also attached below.
Step-by-step explanation:
Given the function
substituting x = 0 in the function
h(0) = 4(0) -2 = 0 -2 = -2
Therefore, the point (0, -2) satisfies on the function.
substituting y = 1 in the function
h(1) = 4(1) -2 = 4 -2 = 2
Therefore, the point (1, 2) satisfies on the function.
substituting y = 2 in the function
h(2) = 4(2) -2 = 8 -2 = 6
Therefore, the point (2, 6) satisfies on the function.
substituting y = 3 in the function
h(3) = 4(3) -2 = 12 -2 = 10
Therefore, the point (3, 10) satisfies on the function.
substituting y = 4 in the function
h(4) = 4(4) -2 = 16 -2 = 14
Therefore, the point (4, 14) satisfies on the function.
substituting y = 5 in the function
h(5) = 4(5) -2 = 20 -2 = 18
Therefore, the point (5, 18) satisfies on the function.
Therefore, we conclude that table:
x h(x) = 4x-2
0 -2
1 2
2 6
3 10
4 14
5 18
The graph of the function h(x) = 4x-2 is also attached below.
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Answer:
0 ≤ t ≤ 5.
Step-by-step explanation:
In the function ,
is the independent variable. The domain of
is the set of all values of
that this function can accept.
In this case, is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,
.
.
The first condition is an inequality about , which is indeed the independent variable.
However, the second condition is about , the dependent variable of this function. It has to be rewritten as a condition about
.
.
Hence, t ≤ 5.
Combine the two inequalities to obtain the domain:
0 ≤ t ≤ 5.