Find the perimeter and area of a rectangle with a width of 2 feet and a length 3 times as long.
2 answers:
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The answer is a =
Step-by-step explanation:
<em>1. Convert the mixed fraction to an improper fraction</em>
To find the numerator, multiply the denominator by the whole number and add the numerator to it.
The denominator remains the same.
So, 2 will be
<em>2. Now the equation is,</em>
a -
a =
+
a
<em>3. Take LCM on both sides. </em>
For the left side, multiply the first fraction by and multiply the second fraction by
a -
a =
<em>4. Solve by making a the subject</em>
=
=
=10+8a
= 10 + 8a
a = 2(10 + 8a)
a = 20 + 16a
a-16a = 20
-15a = 20
a =
a =
Therefore, the answer is a =
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Answer:
Step-by-step explanation:
First, let's look at the largest triangle (two smaller triangles are combined) to solve for . Since the sum of the angles in a triangle adds up to
, we can write the equation:
Looking at the smaller triangle on the left, (exterior angle) is the sum of the two opposite interior angles of the triangle on the left:
Since is the exterior angle of the triangle on the right, it is equivalent to the sum of the opposite interior angles of that triangle:
Hope this helps :)
