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3 years ago

Find the perimeter and area of a rectangle with a width of 2 feet and a length 3 times as long.

Mathematics

2 answers:

rusak2 [61]3 years ago

5 0

Answer:

Length = Width * 3

Width = 2 ft

Length = 2 ft * 3 = 6 ft

Perimeter = (L * 2) + (W * 2)

P = 16 ft

Area = L * W = 12 square feet

prisoha [69]3 years ago

3 0

Answer:

perimeter = 16 ft

area: 12 ft^2

Step-by-step explanation:

length = 3 * width = 3 * 2 = 6 ft

perimeter = (L + W) *2 = 16 ft

area: 12 ft^2

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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

Please help thanks in advance also best answer get's brainlest

Neko [114]

Answer:

angle t is 55 degrees

Step-by-step explanation:

Here's my work:

Isoscelese means two of the same length sides. A triangle is 180 degrees. 180-70=110

110/2=55 (two because those are the two angles associated with the equal sides)

5 0

2 years ago

Add. -3 + (-4) And 4 pluse (-3)

Softa [21]

Answer:

-6

Step-by-step explanation:

-3 + (-4) 4 + (-3) is -6 I hope that helps because that what I got

8 0

3 years ago

Julia has 4 gallons 2 quarts of water.Ally needs the same amount of water but only has 12 quarts.How much more water does Ally n

ozzi

Ok so what do we know :

4 quarts = 1 gal
Julia has 4gal and 2 quarts or 18 quarts
ally has 12 quarts

so if julia has 18 quarts and ally has 12 that means that ally needs 6 more quarts (or 1gal 2 quarts) so that she and julia can have the same amount

8 0

3 years ago

Read 2 more answers

1. Use the inequality 12≥6(12x+2).

svetoff [14.1K]

The answer would be 72x + 12 but I’m not sure but that’s what I got

8 0

3 years ago

Read 2 more answers