Answer:
x = 3/2 or x = -5/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 2 x - 15 = 0
Using the quadratic formula, solve for x.
x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:
x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16
Simplify radicals.
sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:
x = (2 + 22)/16 or x = (2 - 22)/16
Evaluate (2 + 22)/16.
(2 + 22)/16 = 24/16 = 3/2:
x = 3/2 or x = (2 - 22)/16
Evaluate (2 - 22)/16.
(2 - 22)/16 = -20/16 = -5/4:
Answer: x = 3/2 or x = -5/4
Answer:
Step-by-step explanation:
a = -32
2. x=−3/2 ( which also equals -1.5)
Answer:
120
Step-by-step explanation:
As x goes from 1 to 2, y increases by 4 from 4 to 8
As x goes from 2 to 3, y increases by 4 from 8 to 12
We increase by 4 each time
The formula for an arithmetic sequence is
an = a1+d(n-1)
where a1 is the first term which is 4
d is the common difference or the number we add each time which is 4
n is the term we are looking for which is 30
a30 = 4 +4 (30-1)
a30 = 4+4(29)
= 4+116
= 120
The graph is misleading because the sizes compared to the percentages are off. a more appropriate way to show the data would be with a bar graph.
Hope this helps!
Vote me brainliest!
Answer:
Answer:
Green box contains more sugar.
Step-by-step explanation:
Consider the provided information.
Ashley found 2 boxes of sugar in the kitchen.
The green box says 1.26 kg and the red box says 1.026 kg.
we need to find which box contains more sugar.
To find this we will first check the digit at ones place.
Both the digit has 1 at the ones place. So now check the digit at tenths place.
1.26 has 2 at tenths place while 1.026 has 0 at tenths place.
As we know 2 is greater than 0, thus the number 1.26 is greater than 1.026.
Hence, green box contains more sugar.
