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Damm [24]
3 years ago
10

Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in target

ed exercise intensity compared with people who exercise alone. Two methods of collecting data have been proposed.
ᄋ Method I: Recruit volunteers who are willing to participate. Randomly assign each participant to exercise with a training partner or to exercise alone.

ᄋ Method II: Select a random sample of people from all the people who exercise at a community fitness center. Ask each person in the sample whether they use a training partner, and use the response to create the two groups.

(a) For each method, the researchers will record the change in targeted exercise intensity for each person in the investigation. They will compare the mean change in intensity between those who exercise with a training partner and those who do not.


(i) Describe the population of generalization if method I is used.

(ii) Describe the population of generalization if method II is used.

(b) Suppose the investigation produces a result that is statistically significant using both methods. What can be concluded if method I is used that cannot be concluded if method II is used?
Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

we have to compare the effects of method I and method II.

(a)

(i) The population of generalization if the method I is used will be all people who are willing to determine the effect of exercising with a training partner as compared to exercising alone.

(ii) The population of generalization, if method II is used, will be all people who exercise at a community fitness center.

(b)

If both the methods produce significant results then the difference between the conclusion of the method I and the conclusion of method II is that the result of the method I can be generalized to a broader population since it does not restrict people to participate in the study.

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Natasha2012 [34]

Answer:

60,000 grams

Step-by-step explanation:

Find how many grams she weighs by finding how many grams are in 60 kilograms.

There are 1000 grams in a kilogram, so to find her weight in grams, multiply 60 by 1000:

60(1000)

= 60,000

So, Julie weighs 60,000 grams

7 0
3 years ago
Read 2 more answers
Absolute value equations <br> 10 6v + 3 = 30
konstantin123 [22]
Your answers would be 30
7 0
3 years ago
Determine (a) the slope of the line parallel to the line whose slope is m=2 and (b) the slope of the line perpendicular to the l
kotykmax [81]

Answer:

(b) \displaystyle -\frac{1}{2} = m

(a) \displaystyle 2 = m

Step-by-step explanation:

Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], whereas Parallel Lines have SIMILAR <em>RATE OF CHANGES</em> [SLOPES].

I am joyous to assist you anytime.

7 0
3 years ago
A book has 12 chapters. The mean length of the chapters is 40 pages. How many total pages are there in the 12 chapters?
amm1812

Answer:

480

Step-by-step explanation:

Important Information:

A Book Has 12 Chapters.

The Mean length of the chapters is 40 pages.

Question to Answer:

How many total pages are there in the 12 chapters?

Explanation/Solution:

Let's assume that the total number of pages in the book is "x" pages.  

To find the mean (average) we divide the total "x" by 12 because there are 12 chapters in the book, which would equal to 40.  

\frac{x}{12}=40

Multiply both sides by 12...

x = 480

Hence, The total number of pages in the 12 chapters is 480.

7 0
2 years ago
Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0
3 years ago
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