c. We are 95% confident that, among the population of students that play basketball recreationally, the proportion who live on campus is between 0.12 and 0.18.

Step-by-step explanation:

According to the question, it is mentioned that there is 95% confidence interval and it is calculated (0.12,0.18)

So the correct interpretation is that they are 95% confident that the students who play basketballs the proportion should lies between 0.12 and 0.12

So, the option C is correct

The rest of the options are wrong

3 0

3 years ago

Plsss help me with this, Brainlist!!!

irina [24]

Answer:

1. -3

2. 12

youre welcome

4 0

3 years ago

Graph the following inequality :<br> - 2y z x + 6

saul85 [17]

Answer: 2(-2x+3)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio

postnew [5]

The given MGF is that for a random variable following a Poisson distribution with parameter $\lambda=3$ .

This means $\mathbb E(X)=\mathbb V(X)=\lambda$ , and $X$ has PMF

$f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

So, the desired probability is

$\mathbb P\left(\lambda-\lambda^2$

This is equivalent to

$\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232$

8 0

4 years ago