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4vir4ik [10]
3 years ago
12

Y2-x3 when x=2,y=4 x1+x3-y2 when x=3 y=5 x4 divide x3 x=6 please help am bad at this

Mathematics
1 answer:
Katen [24]3 years ago
8 0

Answer:

8 , 5 , 5.785

Step-by-step explanation:

y^2 - x^3

first just plug in the numbers and you get

(4)^2 - (2)^3

Multiply

16-8 and this equals 8

x1 + x^3 - y^2

same pattern plug in the numbers

(3)^(1) + (3)^3 - (5)^2

multiply

3 + 27 - 25

P

E

M

D

Addition

Subtraction so do 3+27 first and you get

30 - 25 = 5

x^4 / x^3 plug it in

(6)^4 / (6)^3

multiply

1269  / 216  

divide this and you get

5.875

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Answer:

2.5% of IQ scores are no more than 65

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 95

Standard deviation = 15

Using the empirical rule, what percentage of IQ scores are no more than 65?

65 = 95 - 2*15

So 65 is two standard deviations below the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviation of the mean. Of those 5% which are not, 2.5% are more than 2 standard deviations above the mean and 2.5% are more than 2 standard deviations below the mean.

So 2.5% of IQ scores are no more than 65

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3 years ago
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Step-by-step explanation:

4√6+5√6

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2 years ago
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A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

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                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
3 years ago
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