Answer with Step-by-step explanation:
Since we have given that
a. f: ℝ → ℝ given by f(x) = x + 2
Domain would be all real numbers i.e. (-∞, ∞)
Range would be all real numbers i.e. (-∞, ∞)
b. g: ℝ → ℝ given by g(x) = √x − 1
Domain would be all positive numbers i.e. [0,∞)
Range would be [-1,∞)
c. f(g(x))

Domain would be [0,∞)
Range would be [3,∞)
d. g(f(x))

Domain would be [-2,∞)
Range would be (0,∞)
I don’t think you can delete questions
Answer:
Step-by-step explanation:
We khow that A is the sum of all odd numbers that are less than 100
So A= 1+3+5+...+99
We can calculate this sum without adding all this numbers one by one
A = the number of terms *( first term + last one ) over 2
To get the number of terms we substract the first term from the last term then we add one
We khow that odd numbers are wiritten this way : 2*n +1 where n is an integer
So 99= 2*49+1
1= 2*0+1
So the number of terms is : 49-0+1 =50
So A= 50*(1+99)/2 = 2500
Foloowing the same method we get :
B= (49-1+1)*(2+98)/2= 2450
A>B