Answer:
4 i think, sorry if incorrect
Step-by-step explanation:
Answer:
We need an SRS of scores of at least 153.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large an SRS of scores must you choose?
This is at least n, in which n is found when
. So







Rounding to the next whole number, 153
We need an SRS of scores of at least 153.
Answer:
The answer is 30°
Step-by-step explanation:

Either heads or tails so there is a 50/50 chance of both
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