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Andrews [41]
3 years ago
15

Y = sec θ tan θ differentiate

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0
Y = sec t tan t = 1/ cos t * sin t / cos t = sin t / cos² t
y`= \frac{cos t cos ^{2} t-2 cost*(-sin t)*sint}{cos^{4} t}= \\  =\frac{cos ^{3} t+2costsin^{2}t }{cos ^{4}t }= \\ = \frac{cos ^{2} t+2sin ^{2} t}{cos ^{3} t}= \\ = \frac{1-sin ^{2}t+2sin ^{2} t }{cos ^{3}t }= \\ = \frac{1+sin ^{2} t}{cos ^{3}t }
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qwelly [4]

Step-by-step explanation:

9:

A=V/t

A=8.0m/s•1/2.0s

A=8.0m/2.0s²

A=4.0m/s²

10:

V=A•time

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sergiy2304 [10]

Answer:

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Step-by-step explanation:

y = -3x + 10 - first equation

y=-3x + 4 - second equation

rearrange the expression to

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pick an equation and simplify; lets pick the second equation

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substitute the value of x into an equation; lets pick the first equation

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divide -2 by both sides

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so the answer is x=1, y=7

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Answer:

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Answer:

Step-by-step explanation:

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=33.414−33.36

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7 girls, because 11(7)+7(10)+147
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