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Andrews [41]
3 years ago
15

Y = sec θ tan θ differentiate

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0
Y = sec t tan t = 1/ cos t * sin t / cos t = sin t / cos² t
y`= \frac{cos t cos ^{2} t-2 cost*(-sin t)*sint}{cos^{4} t}= \\  =\frac{cos ^{3} t+2costsin^{2}t }{cos ^{4}t }= \\ = \frac{cos ^{2} t+2sin ^{2} t}{cos ^{3} t}= \\ = \frac{1-sin ^{2}t+2sin ^{2} t }{cos ^{3}t }= \\ = \frac{1+sin ^{2} t}{cos ^{3}t }
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The missing step in this proof is ∠BAC ≅ ∠BDE ⇒ answer D

Step-by-step explanation:

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