Answer:
see below
Step-by-step explanation:
The exponent rules that apply are ...
(a^b)(a^c) = a^(b+c)
a^-b = (1/a)^b
(a^b)^c = a^(b·c)
_____
These let you rewrite the given function as ...
f(x) = (3^(2x))(3^1) = 3(3^(2x)) = 3(3^2)^x = 3·9^x
and
f(x) = 3^(2x+1) = (3^-1)^(-(2x+1)) = (1/3)^-(2x+1)
The mistake is line 4, she should have divided 42 by 5, not add 5 and 16
Is a collection of well defined and distinct objects.
Ex: ( A B C D E) all letters
Ex2: ( January, February, March, April) all months
Answer:
x=y^2-2
Step-by-step explanation:
This graph, is a parabola that opens to the right.
To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.
In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.
This gives us: x=1(y-0)^2+(-2)
Which simplifies to: x=y^2-2.
Also, the answer to the previous two questions are wrong.
The D value (Domain) is actually [2, ∞)
The R value (Range) is actually "All real numbers" (-∞, ∞)
Let me know if this helps!
Answer:
The answer is 1/3x-1
Step-by-step explanation:
Let's simplify step-by-step.
5/6x−7−(1/2x−6)
Distribute the Negative Sign:
=5/6x−7+−1(1/2x−6)
=5/6x+−7+−1(1/2x)+(−1)(−6)
=5/6x+−7+−1/2x+6
Combine Like Terms:
=5/6x+−7+−1/2x+6
=(5/6x+−1/2x)+(−7+6)
=1/3x+−1
Answer:
=1/3x−1
