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3 years ago

(2) Why do spring balance shows wrong reading after they had been uses for a long time?

2 answers:

7 0

This is because of continuous usage, the wire loses its elasticity and dose not regain it original dimension

densk [106]3 years ago

5 0

Answer:

When a spring balance has been used for a long time, the spring in the balance fatigued and there is loss of strength of the spring. In such a case, the extension in the spring is more for a given load and hence the balance gives wrong readings.

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Which of the following is NOT an example of kinetic energy?

alex41 [277]

An object held in place by gravity

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3 years ago

Read 2 more answers

Once again we have a skier on an inclined plane. The skier has mass M and starts from rest. Her speed at the bottom of the slope

mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

Em₀ = U = m g y

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$Em_{f}$ = K = ½ m v²

As there is no friction, mechanical energy is conserved

Em₀ = $Em_{f}$

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v = √ 2 g y

Where we can use trigonometry to find and

sin 30 = y / L

y = L sin 30

Let's replace

v = RA (2 g L sin 30)

Let's calculate

v = RA (2 9.8 100.0 sin30)

v = 31.3 m / s

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3 years ago

When an object such as a plastic comb is charged by rubbing it with a cloth, the net charge is typically a few microcoulombs. If

masya89 [10]

The concept required to solve this problem is quantization of charge.

First the number of electrons will be calculated and then the total mass of the charge.

With these data it will be possible to calculate the percentage of load in the mass.

$Q= ne$

Here Q is the charge, n is the number of electrons and e is the charge on the electron

$n = \frac{Q}{e}$

Replacing,

$n = \frac{4*10^{-6}C}{1.6*10^{-19}}$

$n = 2.5 * 10^{13}77$

According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron

The total mass of the charge is

$m= nm_e$

Here,

m = Mass of the charge

n = Number of electrons

$m_e$ = Mass of the electron

$\text{Percentage change} = \frac{nm_e}{M}*100$

Replacing we have

$\text{Percentage change} = \frac{(2.5*10^13)(9.1*10^{-28})}{33}*100$

$\text{Percentage change} = 6.9*10^{-14} \%$

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4 years ago

Through the process of transpiration, plants do what?

Evgesh-ka [11]

Well, the process of TRANSPIRATION deals with the release of water to the environment by plants, it is mostly in the form of vapour and is released into the atmosphere. Hope i helped, Have a nice day

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3 years ago

A ball of mass 0.250 kg and a velocity of + 5.00 m/s collides head-on with a ball of mass 0.800 kg that is initially at rest. No

Mademuasel [1]

Answer:

$v_1=-2.616\ m/s$