Answer:
(a) 0.00245 Wb
(b) 0.000645 H
Explanation:
(a) The magnetic flux, Ф, through a coil of radius, r, having N turns due to a magnetic field, B, is given as:
Ф =
where A = area of coil =
Ф = NB
Ф =
Ф = 0.00245 Wb or
(b) If the magnetic flux through the coil vanishes, the magnetic flux due to the coil will be:
Ф =
where L = inductance in the coil and I = current in the coil
Therefore:
L = Ф/I
L = 0.00245/3.8
L = 0.000645 H or
Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:
Then, it means that the net force acting on the test charge has a magnitude of √2F.
Answer: The volume is decreasing at a rate of 80 cm3/min
Explanation: Please see the attachments below
Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;
Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.