A circular coil has a 10.0 cm radius and consists of 30 closely wound turns of wire. An externally produced magnetic field of 2.
1 answer:
Answer:
(a) 0.00245 Wb
(b) 0.000645 H
Explanation:
(a) The magnetic flux, Ф, through a coil of radius, r, having N turns due to a magnetic field, B, is given as:
Ф =
where A = area of coil =
Ф = NB
Ф =
Ф = 0.00245 Wb or
(b) If the magnetic flux through the coil vanishes, the magnetic flux due to the coil will be:
Ф =
where L = inductance in the coil and I = current in the coil
Therefore:
L = Ф/I
L = 0.00245/3.8
L = 0.000645 H or
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Answer:
A. Ein = 8.05*10^-4 V/m
B. Clockwise sense
Explanation:
A. the magnitude of the electric field induced in the ring is obtaind by using the following formula:
(1)
Ein: induced electric field
ds: differential of a path of the ring
ФB: magnetic flux in the ring
The Ein vector is parallel to ds in the complete ring. Furthermore, the area of the ring is constant, hence, you have in the equation (1):
(2)
dB/dt = -0.280T/s (it is decreasing)
A: area of the ring = π(r/2)^2= (π/4) r^2
r: radius of the ring = 4.60/2 = 2.30 cm
Then, you replace the values of all variables in the equation (2):
hence, the induced electric field is 8.05*10^-4 V/m
B. The induced current in the ring produced a magnetic field that is opposite to the magnetic field of the magnet. The, in this case you have that the induced current is in a clockwise sense.